 is modular, so there
is a rational newform
 is modular, so there
is a rational newform 
 which is an eigenform for the 
Hecke operators and an isogeny
 which is an eigenform for the 
Hecke operators and an isogeny  defined over
 defined over 
 , 
which by Hypothesis 4 can be chosen to have degree
coprime to
, 
which by Hypothesis 4 can be chosen to have degree
coprime to  . Indeed, every cyclic rational isogeny is a composition 
of rational isogenies of prime degree, and
. Indeed, every cyclic rational isogeny is a composition 
of rational isogenies of prime degree, and  admits no rational
 admits no rational  -isogeny 
since
-isogeny 
since 
 is irreducible.
 is irreducible.
By Hypothesis 1 the Tamagawa numbers of  are coprime 
to
 are coprime 
to  . Since
. Since  and
 and  are related by an isogeny of degree coprime 
to
 are related by an isogeny of degree coprime 
to  , the Tamagawa numbers of
, the Tamagawa numbers of  are also not divisible by
 are also not divisible by  by Lemma 5.2.6. Moreover, note that
 
by Lemma 5.2.6. Moreover, note that 
 
Let 
 be the ideal of
 be the ideal of 
 generated by
 generated by  and
and 
 for all integers
 for all integers  coprime to
 coprime to  .
Note that
.
Note that 
 is maximal by Lemma 5.2.4.
 is maximal by Lemma 5.2.4.
Let  be as in (3), and let
 be as in (3), and let 
 .
Note that if
.
Note that if 
 then
 then 
 since
 since 
 is attached to a newform, and if, moreover
 is attached to a newform, and if, moreover  , then
, then
 since the Hecke operators with index coprime to
 since the Hecke operators with index coprime to  commute with the degeneracy maps.
Lemma 5.2.1 implies that
commute with the degeneracy maps.
Lemma 5.2.1 implies that
![$\displaystyle E_f[\ell] = E_f[\mathfrak{m}] = \varphi (A_f[\lambda]) \subset A,
$](img397.png) 
so
![$ \Psi = E_f[\ell]$](img398.png) is a subgroup of
 is a subgroup of  as a
as a 
 -module. 
Let
-module. 
Let 
 
where we embed
 in
 in 
 anti-diagonally, i.e., by the map
 anti-diagonally, i.e., by the map
 . 
The antidiagonal map
. 
The antidiagonal map 
 commutes with
the Hecke operators
 commutes with
the Hecke operators  for
 for  , so
, so 
 is preserved by the
 is preserved by the  with
with  .  Let
.  Let  be the subring of
 be the subring of 
 generated by the action of all Hecke operators
generated by the action of all Hecke operators  , with
, with  .
Also note that
.
Also note that 
 acts by Hypothesis 3 as
 acts by Hypothesis 3 as  on
 on
 , but
, but  need not preserve
 need not preserve  .
.
Suppose for the moment that we have verified that the
hypothesis of Theorem 4.1.1 are satisfied with  ,
,  ,
,  ,
,  ,
,  as above and
 as above and 
 .
Then we obtain an injective homomorphism
.
Then we obtain an injective homomorphism
![$\displaystyle E(\mathbb{Q})/\ell E(\mathbb{Q}) \cong E_f(\mathbb{Q})/\ell E_f(\...
...yr}\fontseries{m}\fontshape{n}\selectfont Sh}}}(\mathbb{Q}, C))[\mathfrak{m}].
$](img412.png) 
We then apply Lemma 5.2.2 with  ,
, 
 ,
,  , and
, and  , respectively, to see that
, respectively, to see that  
![$\displaystyle E_f(\mathbb{Q})/\ell E_f(\mathbb{Q}) \subset {\mathrm{Ker}}({\mbo...
...y{wncyr}\fontseries{m}\fontshape{n}\selectfont Sh}}}(\mathbb{Q}, C))[\lambda].
$](img414.png) 
That
 lands in the
 lands in the  -torsion is because
the subgroup of
-torsion is because
the subgroup of 
 that we constructed
is
 that we constructed
is 
 -torsion.
-torsion.
Finally, consider 
 given by
 given by 
 .
Note that
.
Note that  maps to 0
, since
 maps to 0
, since 
 and the elements of
and the elements of  are of the form
 are of the form  .
We have a (not-exact!) sequence of maps
.
We have a (not-exact!) sequence of maps
 
hence inclusions
|  |  |  | |
|  |  | 
It remains to verify the hypotheses of Theorem 4.1.1.
That  is clear from the definition of
 is clear from the definition of  .  Also,
.  Also, 
![$ A\cap E_f = E_f[\ell]$](img426.png) , which is finite. 
We explained above when defining
, which is finite. 
We explained above when defining  that each of
 that each of  and
 and  is preserved by
 is preserved by  .
Since
.
Since 
 and
 and  is odd the condition
 is odd the condition 
 is satisfied.
That
 is satisfied.
That 
 is finite follows from our hypothesis
that
 is finite follows from our hypothesis
that 
 (by [KL89]).
 (by [KL89]).
It remains is to verify that the groups
![$\displaystyle Q(\mathbb{Q})[\mathfrak{m}] ,\quad E_f(\mathbb{Q})[\mathfrak{m}] ,\quad \Phi_{A,q}(\mathbb{F}_q)[\mathfrak{m}] ,$](img430.png) and
    and ![$\displaystyle \Phi_{E_f,q}(\mathbb{F}_q)[\ell] ,
$](img431.png) 
are 0 for all primes
 .
Since
.
Since 
 , we have by Hypothesis 4 that
, we have by Hypothesis 4 that
![$\displaystyle E_f(\mathbb{Q})[\mathfrak{m}] = E_f(\mathbb{Q})[\ell] = 0.
$](img434.png) 
We will now verify that 
![$ Q(\mathbb{Q})[\mathfrak{m}]=0$](img435.png) .
From the definition of
.
From the definition of  and
 and  we have
 we have 
 Let
Let  be as in Lemma 5.2.4 with
 be as in Lemma 5.2.4 with 
 .
The map
.
The map  induces an isogeny of
 induces an isogeny of  -power degree
-power degree
![$\displaystyle A_f/(A_f[\lambda]) \to A/\Psi.
$](img438.png) 
Thus there is
 -torsion in
-torsion in 
![$ (A_f/(A_f[\lambda]))(\mathbb{Q})$](img439.png) if and only if there is
if and only if there is 
 -torsion in
-torsion in 
 . 
Thus it suffices to prove that
. 
Thus it suffices to prove that 
![$ (A_f/A_f[\lambda])(\mathbb{Q})[\lambda_p] = 0$](img441.png) .
.
By Lemma 5.2.4, we have 
 , and
by Lemma 5.2.5,
, and
by Lemma 5.2.5, 
![$\displaystyle (A_f/A_f[\lambda])[\lambda] \cong A_f[\lambda^2]/A_f[\lambda].
$](img443.png) 
By [Maz77, § II.14], the quotient
![$ A_f[\lambda^2]/A_f[\lambda]$](img444.png) injects into a direct sum of copies of
injects into a direct sum of copies of 
![$ A_f[\lambda]$](img445.png) as Galois
modules.  But
 as Galois
modules.  But 
![$ A_f[\lambda] \cong E[\ell]$](img446.png) is irreducible, so
 is irreducible, so
![$ (A_f[\lambda^2]/A_f[\lambda])(\mathbb{Q}) = 0$](img447.png) , as required.
, as required.
By Hypothesis 2, we have 
![$ \Phi_{A_f,q}(\mathbb{F}_q)[\lambda] = 0$](img448.png) for each prime 
divisor
 for each prime 
divisor  .Since
.Since  is
 is  -power isogenous to
-power isogenous to  and
 and  is odd, this
verifies the Tamagawa number hypothesis for
 is odd, this
verifies the Tamagawa number hypothesis for  .  Our hypothesis that
.  Our hypothesis that
 implies that
 implies that 
 acts on
 acts on 
 as
 as
 .  Thus
.  Thus 
![$ \Phi_{E_f,p}(\mathbb{F}_p)[\ell] = 0$](img451.png) since
 since  is odd.
This completes the proof.
 is odd.
This completes the proof.
  
 of the curves
 of the curves  that are intermediate 
covers for the covering
 that are intermediate 
covers for the covering 
 corresponding to subgroups
 corresponding to subgroups 
 (i.e., the Galois group of
 (i.e., the Galois group of 
 is
 
is  ), one should be able to give a generalization of Theorem 5.1.3 
which holds for newform subvarieties of
), one should be able to give a generalization of Theorem 5.1.3 
which holds for newform subvarieties of  . This
requires generalizing some results from [Rib90b] to arbitrary
. This
requires generalizing some results from [Rib90b] to arbitrary  .
.  William Stein 2006-06-21